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-3x^2+3x=-5x
We move all terms to the left:
-3x^2+3x-(-5x)=0
We get rid of parentheses
-3x^2+3x+5x=0
We add all the numbers together, and all the variables
-3x^2+8x=0
a = -3; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-3)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-3}=\frac{-16}{-6} =2+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-3}=\frac{0}{-6} =0 $
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